If I\'m using compass for CSS and use a function or mixin like:
@include background-image(linear-gradient(#a3cce0, #fff));
is there any
I had this problem last time and I overrided the compass style with a stronger selector. I just added an ID on my html element
span { @include border-radius(5px);}
span#no-radius { @include border-radius(0px); } // override
You can include it inside the mixin like so:
@include border-radius(5px !important);
Compass will output the following:
-webkit-border-radius: 5px !important;
-moz-border-radius: 5px !important;
-ms-border-radius: 5px !important;
-o-border-radius: 5px !important;
border-radius: 5px !important;
UPDATE: new versions of sass support this syntax now:
@include border-radius(5px !important);
Just do this (as noted in @naoufal answer).
--- old answer ---
You can not use !important with compass mixings, but the culprit is not compass, you should blame sass for this.
@include border-radius(5px) !important; #=> SASS Syntax Error
Actually you can use a @function
to handle the !important
while keeping the flexibility of the mixing itself. For example:
@function is-important($important){
@return #{if($important, '!important', '')};
}
// by default we don't want the !important at the end
@mixin button-primary($important: false) {
font-size: 14px;
background: #fff is-important($important);
color: #000 is-important($important);
}
Hope it helps!
This question came up in my search for a similar problem, it's spot on but I just wanted to add that Making a Sass mixin with optional arguments was another possible approach that I found useful.
Replace inset
with important
and pass !important
in when you need it.
Just spent hours figuring this out but there is a quick trick you can do. At the top of your SASS file add the following:
$i: unquote("!important");
in your style do the following:
color: #CCCCCC $i;
output is:
color: #CCCCCC !important;
full sample:
$i: unquote("!important");
.some-style {
color: white $i;
}
output:
.some-style {
color: white !important;
}