Start a loop from 1

Question

I recently came upon the scary idea that Integer.count loops in Ruby start from 0 and go to n-1 while playing with the Facebook Engine

Answer 1

You could use a range:

(1..10).each { |i| puts i }

Ranges give you full control over the starting and ending indexes (as long as you want to go from a lower value to a higher value).

Answer 2

There is of course the while-loop:

i = 1
while i<=10 do
  print "#{i} "
  i += 1
end
# Outputs: 1 2 3 4 5 6 7 8 9 10

Answer 3

Ruby supports a number of ways of counting and looping:

1.upto(10) do |i|
  puts i
end

>> 1.upto(10) do |i|
 >     puts i
|    end #=> 1
1
2
3
4
5
6
7
8
9
10

There's also step instead of upto which allows you to increment by a step value:

>> 1.step(10,2) { |i| puts i } #=> 1
1
3
5
7
9

Answer 4

Try

(1..10).each do |i|
 #  ... i goes from 1 to 10
end

instead. It is also easier to read when the value of i matters.

Answer 5

Old, but this might be something somebody's lookin for..

5.times.with_index(100){|i, idx| p i, idx};nil
#=>
    0
    100
    1
    101
    2
    102
    3
    103
    4
    104