Use scrapy to get list of urls, and then scrape content inside those urls

Question

I need a Scrapy spider to scrape the following page (https://www.phidgets.com/?tier=1&catid=64&pcid=57) for each URL (30 products, so 30 urls) and then go into each

Answer 1

I am not able to test at this moment, so please let me know if this works for you so I can edit it should there be any bugs.

The idea here is that we find every link in the first page and yield new scrapy requests passing your product parsing method as a callback

import scrapy
from urllib.parse import urljoin

class ProductsSpider(scrapy.Spider):
    name = "products"
    start_urls = [
        'https://www.phidgets.com/?tier=1&catid=64&pcid=57',
    ]

    def parse(self, response):
        products = response.xpath("//*[contains(@class, 'ph-summary-entry-ctn')]/a/@href").extract()
        for p in products:
            url = urljoin(response.url, p)
            yield scrapy.Request(url, callback=self.parse_product)

    def parse_product(self, response):
        for info in response.css('div.ph-product-container'):
            yield {
                'product_name': info.css('h2.ph-product-name::text').extract_first(),
                'product_image': info.css('div.ph-product-img-ctn a').xpath('@href').extract(),
                'sku': info.css('span.ph-pid').xpath('@prod-sku').extract_first(),
                'short_description': info.css('div.ph-product-summary::text').extract_first(),
                'price': info.css('h2.ph-product-price > span.price::text').extract_first(),
                'long_description': info.css('div#product_tab_1').extract_first(),
                'specs': info.css('div#product_tab_2').extract_first(),
            }