How to detect the visitor's IP address using HTML?

Question

How can i detect the visitors IP Address using HTML for my website? I have a contactform.html and a formsent.html. And when formsent.html sends the contact info to my email

Answer 1

The following script may be useful to you. You can copy it and save it as {whateveryouwant}.php

<?php

echo "Your IP is";

echo $_SERVER["REMOTE_ADDR"];

function get_ip_address() {
  // check for shared internet/ISP IP
  if (!empty($_SERVER['HTTP_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_CLIENT_IP']))
   return $_SERVER['HTTP_CLIENT_IP'];

  // check for IPs passing through proxies
  if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
   // check if multiple ips exist in var
    $iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
    foreach ($iplist as $ip) {
     if ($this->validate_ip($ip))
      return $ip;
    }
   }

  if (!empty($_SERVER['HTTP_X_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_X_FORWARDED']))
   return $_SERVER['HTTP_X_FORWARDED'];
  if (!empty($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']))
   return $_SERVER['HTTP_X_CLUSTER_CLIENT_IP'];
  if (!empty($_SERVER['HTTP_FORWARDED_FOR']) && $this->validate_ip($_SERVER['HTTP_FORWARDED_FOR']))
   return $_SERVER['HTTP_FORWARDED_FOR'];
  if (!empty($_SERVER['HTTP_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_FORWARDED']))
   return $_SERVER['HTTP_FORWARDED'];

  // return unreliable ip since all else failed
   return $_SERVER['REMOTE_ADDR'];
 }

function validate_ip($ip) {
     if (filter_var($ip, FILTER_VALIDATE_IP, 
                         FILTER_FLAG_IPV4 | 
                         FILTER_FLAG_IPV6 |
                         FILTER_FLAG_NO_PRIV_RANGE | 
                         FILTER_FLAG_NO_RES_RANGE) === false)
         return false;
     self::$ip = $ip;
     return true;
 }
?>

Answer 2

HTML is a markup language, so it doesn't have any variables.

If you want to get it using PHP, you'll need to make use of the $_SERVER superglobal variable. A solution could be:

echo $_SERVER["REMOTE_ADDR"];

This actually gets the host ip, which would be your server.

echo $_SERVER["REMOTE_ADDR"];

This is the most basic however, and fails if the user is behind a proxy, as well as allowing them to trivially change it. A much much better method is to using something like:

function get_ip_address() {
  // check for shared internet/ISP IP
  if (!empty($_SERVER['HTTP_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_CLIENT_IP']))
   return $_SERVER['HTTP_CLIENT_IP'];

  // check for IPs passing through proxies
  if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
   // check if multiple ips exist in var
    $iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
    foreach ($iplist as $ip) {
     if ($this->validate_ip($ip))
      return $ip;
    }
   }

  if (!empty($_SERVER['HTTP_X_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_X_FORWARDED']))
   return $_SERVER['HTTP_X_FORWARDED'];
  if (!empty($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']))
   return $_SERVER['HTTP_X_CLUSTER_CLIENT_IP'];
  if (!empty($_SERVER['HTTP_FORWARDED_FOR']) && $this->validate_ip($_SERVER['HTTP_FORWARDED_FOR']))
   return $_SERVER['HTTP_FORWARDED_FOR'];
  if (!empty($_SERVER['HTTP_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_FORWARDED']))
   return $_SERVER['HTTP_FORWARDED'];

  // return unreliable ip since all else failed
  return $_SERVER['REMOTE_ADDR'];
 }

function validate_ip($ip) {
     if (filter_var($ip, FILTER_VALIDATE_IP, 
                         FILTER_FLAG_IPV4 | 
                         FILTER_FLAG_IPV6 |
                         FILTER_FLAG_NO_PRIV_RANGE | 
                         FILTER_FLAG_NO_RES_RANGE) === false)
         return false;
     self::$ip = $ip;
     return true;
 }

(http://stackoverflow.com/questions/1634782/what-is-the-most-accurate-way-to-retrieve-a-users-correct-ip-address-in-php)

This correctly parses the HTTP_X_FORWARDED_FOR field as well as validating the IP to make sure it's of the right format, and not in a private block.

Answer 3

$ip=$_SERVER['REMOTE_ADDR'];

this command shows server ip address not user local ip address because this is php command is complies the code in server because of that reason this command show server ip address

Answer 4

You can't, not through HTML alone.

You need to use scripting that has the HTTP headers available to it.

See this SO answer using JSONP.

For PHP you would use $_SERVER['REMOTE_HOST'].

Answer 5

You can't.

HTML is a markup language, not a programming language. it doesn't "do" anything - it just structures content.

You need to use a programming language, such as PHP, ASP, etc.

Answer 6

You can't do it through HTML. However, you can find the IP address of a visitor through PHP.

$ip=$_SERVER['REMOTE_ADDR'];