Django counter in loop to index list

Question

I\'m passing two lists to a template. Normally if I was iterating over a list I would do something like this

{% for i in list %}

but I hav

Answer 1

You can't. The simple way is to preprocess you data in a zipped list, like this

In your view

x = [1, 2, 3]
y = [4, 5, 6]
zipped = zip(x, y)

Then in you template :

{% for x, y in zipped %}
    {{ x }} - {{ y }}
{% endfor %}

Answer 2

Sounds like you're looking for my django-multiforloop. From the README:

Rendering this template

{% load multifor %}
{% for x in x_list; y in y_list %}
  {{ x }}:{{ y }}
{% endfor %}

with this context

context = {
    "x_list": ('one', 1, 'carrot'),
    "y_list": ('two', 2, 'orange')
}

will output

one:two
1:2
carrot:orange

Answer 3

don't think you'll be able to do it like that. You'll need either a template tag, or much better, to align the lists in your view logic, before passing an aligned data structure to you template.

Answer 4

I ended up having to do this:

{% for x in x_list %}
  {% for y in y_list %}
    {% if forloop.counter == forloop.parentloop.counter %}
       Do Something
    {% endif %}
  {% endfor %}
{% endfor %}

Answer 5

To access an iterable using a forloop counter I've coded the following very simple filter:

from django import template

register = template.Library()

@register.filter
def index(sequence, position):
    return sequence[position]

And then I can use it at my templates as (don't forget to load it):

{% for item in iterable1 %}
  {{ iterable2|index:forloop.counter0 }}
{% endfor %}

Hope this helps someone else!