First, I am very new to SPARK
I have millions of records in my Dataset and i wanted to groupby with name column and finding names which having maximum age. I am gett
What your trying to achieve is
This alternative achieves this output without use of aggregate
import org.apache.spark.sql._
import org.apache.spark.sql.expressions.Window
import org.apache.spark.sql.functions._
object TestJob5 {
def main (args: Array[String]): Unit = {
val sparkSession = SparkSession
.builder()
.appName(this.getClass.getName.replace("$", ""))
.master("local")
.getOrCreate()
val sc = sparkSession.sparkContext
sc.setLogLevel("ERROR")
import sparkSession.sqlContext.implicits._
val rawDf = Seq(
("Moe", "Slap", 7.9, 118),
("Larry", "Spank", 8.0, 115),
("Curly", "Twist", 6.0, 113),
("Laurel", "Whimper", 7.53, 119),
("Hardy", "Laugh", 6.0, 118),
("Charley", "Ignore", 9.7, 115),
("Moe", "Spank", 6.8, 118),
("Larry", "Twist", 6.0, 115),
("Charley", "fall", 9.0, 115)
).toDF("name", "requisite", "funniness_of_requisite", "age")
rawDf.show(false)
rawDf.printSchema
val nameWindow = Window
.partitionBy("name")
val aggDf = rawDf
.withColumn("id", monotonically_increasing_id)
.withColumn("maxFun", max("funniness_of_requisite").over(nameWindow))
.withColumn("count", count("name").over(nameWindow))
.withColumn("minId", min("id").over(nameWindow))
.where(col("maxFun") === col("funniness_of_requisite") && col("minId") === col("id") )
.drop("maxFun")
.drop("minId")
.drop("id")
aggDf.printSchema
aggDf.show(false)
}
}
bear in mind that a group could potentially have more than 1 row with max age so you need to pick one by some logic. In the example I assume it doesn't matter so I just assign a unique number to choose
You need to remember that aggregate functions reduce the rows and therefore you need to specify which of the rows age you want with a reducing function. If you want to retain all rows of a group (warning! this can cause explosions or skewed partitions) you can collect them as a list. You can then use a UDF (user defined function) to reduce them by your criteria, in this example funniness_of_requisite. And then expand columns belonging to the reduced row from the single reduced row with another UDF . For the purpose of this answer I assume you wish to retain the age of the person who has the max funniness_of_requisite.
import org.apache.spark.sql._
import org.apache.spark.sql.catalyst.expressions.GenericRowWithSchema
import org.apache.spark.sql.functions._
import org.apache.spark.sql.types.{IntegerType, StringType}
import scala.collection.mutable
object TestJob4 {
def main (args: Array[String]): Unit = {
val sparkSession = SparkSession
.builder()
.appName(this.getClass.getName.replace("$", ""))
.master("local")
.getOrCreate()
val sc = sparkSession.sparkContext
import sparkSession.sqlContext.implicits._
val rawDf = Seq(
(1, "Moe", "Slap", 7.9, 118),
(2, "Larry", "Spank", 8.0, 115),
(3, "Curly", "Twist", 6.0, 113),
(4, "Laurel", "Whimper", 7.53, 119),
(5, "Hardy", "Laugh", 6.0, 18),
(6, "Charley", "Ignore", 9.7, 115),
(2, "Moe", "Spank", 6.8, 118),
(3, "Larry", "Twist", 6.0, 115),
(3, "Charley", "fall", 9.0, 115)
).toDF("id", "name", "requisite", "funniness_of_requisite", "age")
rawDf.show(false)
rawDf.printSchema
val rawSchema = rawDf.schema
val fUdf = udf(reduceByFunniness, rawSchema)
val nameUdf = udf(extractAge, IntegerType)
val aggDf = rawDf
.groupBy("name")
.agg(
count(struct("*")).as("count"),
max(col("funniness_of_requisite")),
collect_list(struct("*")).as("horizontal")
)
.withColumn("short", fUdf($"horizontal"))
.withColumn("age", nameUdf($"short"))
.drop("horizontal")
aggDf.printSchema
aggDf.show(false)
}
def reduceByFunniness= (x: Any) => {
val d = x.asInstanceOf[mutable.WrappedArray[GenericRowWithSchema]]
val red = d.reduce((r1, r2) => {
val funniness1 = r1.getAs[Double]("funniness_of_requisite")
val funniness2 = r2.getAs[Double]("funniness_of_requisite")
val r3 = funniness1 match {
case a if a >= funniness2 =>
r1
case _ =>
r2
}
r3
})
red
}
def extractAge = (x: Any) => {
val d = x.asInstanceOf[GenericRowWithSchema]
d.getAs[Int]("age")
}
}
d.getAs[String]("name")
}
}
here is the output
+-------+-----+---------------------------+-------------------------------+---+
|name |count|max(funniness_of_requisite)|short
|age|
+-------+-----+---------------------------+-------------------------------+---+
|Hardy |1 |6.0 |[5, Hardy, Laugh, 6.0, 18]
|18 |
|Moe |2 |7.9 |[1, Moe, Slap, 7.9, 118]
|118|
|Curly |1 |6.0 |[3, Curly, Twist, 6.0, 113]
|113|
|Larry |2 |8.0 |[2, Larry, Spank, 8.0, 115]
|115|
|Laurel |1 |7.53 |[4, Laurel, Whimper, 7.53, 119]|119|
|Charley|2 |9.7 |[6, Charley, Ignore, 9.7, 115] |115|
+-------+-----+---------------------------+-------------------------------+---+
For your solution you have to try different approach. You was almost there for solution but let me help you understand.
Dataset<Row> resultset = studentDataSet.groupBy("name").max("age");
now what you can do is you can join the resultset
with studentDataSet
Dataset<Row> joinedDS = studentDataset.join(resultset, "name");
The problem with groupBy
this that after applying groupBy you get RelationalGroupedDataset
so it depends on what next operation you perform like sum, min, mean, max
etc then the result of these operation joined with groupBy
As in you case name
column is joined with the max
of age
so it will return only two columns but if use apply groupBy
on age
and then apply max
on 'age' column you will get two column one is age
and second is max(age)
.
Note :- code is not tested please make changes if needed Hope this clears you query
Noting that a subsequent join is extra shuffling and some of the other solutions seem inaccurate in the returns or even turn the Dataset into Dataframes, I sought a better solution. Here is mine:
case class People(name: String, age: Int, other: String)
val df = Seq(
People("Rob", 20, "cherry"),
People("Rob", 55, "banana"),
People("Rob", 40, "apple"),
People("Ariel", 55, "fox"),
People("Vera", 43, "zebra"),
People("Vera", 99, "horse")
).toDS
val oldestResults = df
.groupByKey(_.name)
.mapGroups{
case (nameKey, peopleIter) => {
var oldestPerson = peopleIter.next
while(peopleIter.hasNext) {
val nextPerson = peopleIter.next
if(nextPerson.age > oldestPerson.age) oldestPerson = nextPerson
}
oldestPerson
}
}
oldestResults.show
The following produces:
+-----+---+------+
| name|age| other|
+-----+---+------+
|Ariel| 55| fox|
| Rob| 55|banana|
| Vera| 99| horse|
+-----+---+------+
The accepted answer isn't ideal because it requires a join. Joining big DataFrames can cause a big shuffle that'll execute slowly.
Let's create a sample data set and test the code:
val df = Seq(
("bob", 20, "blah"),
("bob", 40, "blah"),
("karen", 21, "hi"),
("monica", 43, "candy"),
("monica", 99, "water")
).toDF("name", "age", "another_column")
This code should run faster with large DataFrames.
df
.groupBy("name")
.agg(
max("name").as("name1_dup"),
max("another_column").as("another_column"),
max("age").as("age")
).drop(
"name1_dup"
).show()
+------+--------------+---+
| name|another_column|age|
+------+--------------+---+
|monica| water| 99|
| karen| hi| 21|
| bob| blah| 40|
+------+--------------+---+