How to validate Password Field in android?

Question

Hi I am very new for android and in my app I have Validations for Change password page.

That means the Password must contain minimum 8 characters at least 1 Alphabet

Answer 1

Simple and sort, just use below method for checking valid password,

public static boolean isValidPassword(String password) {
    Matcher matcher = Pattern.compile("((?=.*[a-z])(?=.*\\d)(?=.*[A-Z])(?=.*[@#$%!]).{4,20})").matcher(password);
    return matcher.matches();
}

and you can use this method as below

          if (!isValidPassword(edtPassword.getText().toString())) {
                errorDialog("Password must contain mix of upper and lower case letters as well as digits and one special charecter(4-20)");
                }

Answer 2

easy piece of code for email field validation and password validation and check for minimum 8 characters in password field.

  if (isValidEmail(et_regemail.getText().toString())&&etpass1.getText().toString().length()>7){
      if (validatePassword(etpass1.getText().toString())) {
      Toast.makeText(getApplicationContext(),"Go Ahead".....
      }
      else{

       Toast.makeText(getApplicationContext(),"InvalidPassword".....
       }

}else{

 Toast.makeText(getApplicationContext(),"Invalid Email".....
}


public boolean validatePassword(final String password){
    Pattern pattern;
    Matcher matcher;
    final String PASSWORD_PATTERN = "^(?=.*[0-9])(?=.*[A-Z])(?=.* 
    [@#$%^&+=!])(?=\\S+$).{4,}$";
    pattern = Pattern.compile(PASSWORD_PATTERN);
    matcher = pattern.matcher(password);

    return matcher.matches();
}

public final static boolean isValidEmail(CharSequence target) {
    if (target == null)
        return false;

    return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}

Answer 3

public static boolean passwordCharValidation(String passwordEd) {
    String PASSWORD_PATTERN = "^(?=.*[A-Z])(?=.*[@_.]).*$";
    Pattern pattern = Pattern.compile(PASSWORD_PATTERN);
    Matcher matcher = pattern.matcher(passwordEd);
    if (!passwordEd.matches(".*\\d.*") || !matcher.matches()) {
        return true;
    }
    return false;
}

Answer 4

Passwords do not match

if  (password.getText().toString() != reEnteredPassword.getText().toString()) {
//not match
}

For Empty Fields

if (password.getText().toString().isEmpty() || reEnteredPassword.getText().toString().isEmpty()) {
//Fieds empty error message

Less than 8 characters

if ((password.getText().toString().length() < 8) || (reEnteredPassword.getText().toString().length() < 8)) {
// less than 8 characters error message
}

Not having special characters

if (!password.getText().toString().matches( "^(?=.*[0-9])(?=.*[a-z])(?=.*[!@#$%^&*+=?-]).{8,15}$") || !reEnteredPassword.getText().toString().matches( "^(?=.*[0-9])(?=.*[a-z])(?=.*[!@#$%^&*+=?-]).{8,15}$")){
//not having special characters error message
}

Answer 5

Try this it works

   public static boolean isPasswordValidMethod(final String password) {

    Pattern pattern;
    Matcher matcher;
    final String PASSWORD_PATTERN = "^(?=.*[A-Za-z])(?=.*\\\\d)(?=.*[$@$!%*#?&])[A-Za-z\\\\d$@$!%*#?&]{8,}$""
    pattern = Pattern.compile(PASSWORD_PATTERN);
    matcher = pattern.matcher(password);

    return matcher.matches();

}

Answer 6

public static boolean isValidPassword(String s) {
            Pattern PASSWORD_PATTERN
                    = Pattern.compile(
                    "[a-zA-Z0-9\\!\\@\\#\\$]{8,24}");

            return !TextUtils.isEmpty(s) && PASSWORD_PATTERN.matcher(s).matches();
        }

to use it,

if(isValidPassword(password)){ //password valid}

You can set whatever symbol that you allowed here