jQuery - submit multiple forms through single request, without Ajax

Question

I have a page with several forms. I am trying to submit one of the forms (say form A) (NOT through Ajax, since I need to load the result page after the submit is processed)

Answer 1

I discovered that your solution will copy the form to another invissible form, but the backside is that the original forms will be cleared an such edit of the original form (eg after form validation errors) is not possible.

To solve this i tried to clone the elements before appending it to the invissible form. I edited your code like this:

//Arguments: "name"s of forms to submit.
//First argument: the form which according to its "action" all other forms will be submitted.
//Example: mergeForms("form1","form2","form3","form4")    
function mergeForms() {
        var forms = [];
        $.each($.makeArray(arguments), function(index, value) {
            forms[index] = document.forms[value];
        });
        var targetForm = forms[0];
        $.each(forms, function(i, f) {
            if (i != 0) {
                $(f).find('input, select, textarea')
                    .clone()
                    .hide()
                    .appendTo($(targetForm));
            }
        });

Unfortunatly now it doesn't copy the selected values in a select element.

Hope someone can help me to impove this script

Answer 2

you can do some thing like this

$('#SubmitBtn).click(function () {
        $("#formId").attr("action", "http://www.YourSite.com/");
        $("#formId").attr("method", "post");
        $("#formId").attr("target","_blank");
        $('#formId').submit();
    });

this will submit the for to http://www.YourSite.com/ in a new window

Answer 3

You can only do one request at a time and that will reload the page unless you use AJAX. The only other option would be to create a script which concatantes the seralizations of your two forms - but at that point, why wouldn't you just use one large form..

Edit: For your combining the two forms, there is an example of this in the answer of the second link you provided.

Answer 4

A solution to inject the data directly in the post request (and not in a sub field)

<form id="form1">
    <input ... />
    <input ... />
</form>

<form id="form2">
    <input ... />
    <input ... />
</form>

<form id="result" action="..." method="POST" onsubmit="merge(); return true;">
    <input type="submit" />
</form>


<script type="text/javascript">
    function merge() {
        $result = $("#result");
        $("#form1 input, #form2 input, #form1 select, #form2 select, #form1 textarea, #form2 textarea").each(function() {
            $result.append("<input type='hidden' name='"+$(this).attr('name')+"' value='"+$(this).val()+"' />");
        });
    }
</script>

Answer 5

form A:

<form method="post" action="next.html" onsubmit="this.formbVal.value = $('#formb').serialize(); return true;">
    <input type="hidden" name="formbVal" value="" />
    <input type="submit">
</form>

form B:

<form id="formb" method="post" action="#" onsubmit="return false;">
</form>

Answer 6

Well, you have to copy the data from form2 to form1 before the submit. Here is the basic to get you started:

$.each ( $('#form2 input, #form2 select, #form2 textarea').serializeArray(), function ( i, obj ) {
  $('<input type="hidden">').prop( obj ).appendTo( $('#form1') );
} );

This function would select inputs from form2, get their current values, then create a new hidden input for each of them and add them to form1.

Depending on your scenario you may want to check the existance of input with same name on form1 first.