replace array keys with given respective keys

Question

I have an array like below

$old = array(
       \'a\' => \'blah\',
       \'b\' => \'key\',
       \'c\' => \'amazing\',
       \'d\' => array(
          


        

Answer 1

This works irrespective of array order & array count. Output order & value will be based on replaceKey.

$replaceKey = array('a' => 'newA', 'b' => 'newB', 'c' => 'newC', 'd' => 'newD', 'e' => 'newE','f'=>'newF');

$array = array(
       'a' => 'blah',
       'd' => array(
                0 => 'want to replace',
                1 => 'yes I want to'
              ),
       'noKey'=>'RESIDUAL',
       'c' => 'amazing',
       'b' => 'key',
       );

$filterKey = array_intersect_key($replaceKey,$array);
$filterarray = array_intersect_key(array_merge($filterKey,$array),$filterKey);

$replaced = array_combine($filterKey,$filterarray);

//output
var_export($replaced);
//array ( 'newA' => 'blah', 'newB' => 'key', 'newC' => 'amazing', 'newD' => array ( 0 => 'want to replace', 1 => 'yes I want to' ) )

Answer 2

    <?php
$new = array(); 

foreach ($old as $key => $value)
{
     $new[$keyReplaceInfoz][$key] = $value;

}
?>

Answer 3

IMO using array_combine, array_merge, even array_intersect_key is overkill. The original code is good enough, and very fast.

Answer 4

<?php
$old = array(
       'a' => 'blah',
       'b' => 'key',
       'c' => 'amazing',
       'd' => array(
                0 => 'want to replace',
                1 => 'yes I want to'
              )
       );
$keyReplaceInfoz = array('a' => 'newA', 'b' => 'newB', 'c' => 'newC', 'd' => 'newD');

$new = array(); 

foreach ($old as $key => $value)
{
    $newvalue =  $keyReplaceInfoz[$key];
   $new[$key] = $newvalue;
}
print_r($new);

?>