Order By month and year in sql with sum

Question

I have a stored procedure and the select statement is:

SELECT     { fn MONTHNAME(OrderDate) } AS MonthName, YEAR(OrderDate) AS Year, SUM(TotalValue) AS Profi         


        

Answer 1

If you want to order as Jan, Feb, March use

SELECT 
  month(OrderDate) MonthName, 
  year(OrderDate) Year, 
  sum(TotalValue) Profits
FROM         
  [Order]
WHERE     
  month(OrderDate) = @year
ORDER BY 
  year(OrderDate), 
  month(OrderDate)
GROUP BY 
  year(OrderDate),
  month(OrderDate)

Answer 2

I think you should use order by clause at the end

SELECT     { fn MONTHNAME(OrderDate) } AS MonthName, YEAR(OrderDate) AS Year, SUM(TotalValue) AS Profits
FROM         [Order]
WHERE     (YEAR(OrderDate) = @year)
GROUP BY { fn MONTHNAME(OrderDate) }, YEAR(OrderDate) 
ORDER BY { fn MONTH(OrderDate) }, YEAR(OrderDate)

or

you can do like this

SELECT     CASE { fn MONTH(OrderDate) } 
            when 0 then 'JAN'
            when 1 then 'FEB'
            when 2 then 'MAR'
            when 3 then 'APR'
            when 4 then 'MAY'
            when 5 then 'JUN'
            when 6 then 'JUL'
            when 7 then 'AUG'
            when 8 then 'SEP'
            when 9 then 'OCT'
            when 10 then 'NOV'
            when 11 then 'DEC'
           END
      AS MonthName, YEAR(OrderDate) AS Year, SUM(TotalValue) AS Profits
    FROM         [Order]
    WHERE     (YEAR(OrderDate) = @year)
    GROUP BY { fn MONTH(OrderDate) }, YEAR(OrderDate) 
    ORDER BY { fn MONTH(OrderDate) }, YEAR(OrderDate)

Answer 3

Try this. It works perfectly. Note that you already entering a year value. So you don't need to order or group Year since you can only choose one Year at a time. So the extra code is not needed.

SELECT { fn MONTHNAME(OrderDate) } AS MonthName, SUM(TotalValue) AS Profits
FROM [Order]
WHERE (YEAR(OrderDate) = @year)
GROUP BY { fn MONTHNAME(OrderDate) }, DATEPART(M, OrderDate)
ORDER BY DATEPART(M, OrderDate)

Answer 4

Just add

Order by max(OrderDate) 

at the end.

SELECT     { fn MONTHNAME(OrderDate) } AS MonthName, YEAR(OrderDate) AS Year,     SUM(TotalValue) AS Profits
FROM         [Order]
WHERE     (YEAR(OrderDate) = @year)
GROUP BY { fn MONTHNAME(OrderDate) }, YEAR(OrderDate)
Order by max(OrderDate) 

Now about how it works:

If you order by month , year separately, it will go in ascending order of month in alphabetical order (April before January). If you order by order date id will be ordered based on a date value which is of course ordered by month/year.

Answer 5

select 
cast(year(appointmentdate) as char(4))+''+ 
case when len(cast(month(appointmentdate)as char(2)))=1 
then '0'+cast(  month(appointmentdate) as char(2) ) else cast(month(appointmentdate) as char(2))end  as apporder
from timeslots  
group by appointmentdate
order by appOrder

Answer 6

Use Following query it will work for you.

SELECT     { fn MONTHNAME(OrderDate) } AS MonthName, datepart(MM,OrderDate)                     AS Month, YEAR(OrderDate) AS Year, SUM(TotalValue) AS Profits
FROM         [Order]
WHERE     (YEAR(OrderDate) = @year)
GROUP BY { fn MONTHNAME(OrderDate) }, YEAR(OrderDate),     datepart(MM,**OrderDate**) 
ORDER BY datepart(MM,**OrderDate**)