How to get a particular date format ('dd-MMM-yyyy') in SELECT query SQL Server 2008 R2

Question

I am using CONVERT(data_type(length),expression,style) function to change the format of a date in a SELECT query.

Declare @dt nvarchar(20)

Answer 1

select convert(varchar(11), transfer_date, 106)

got me my desired result of date formatted as 07 Mar 2018

My column transfer_date is a datetime type column and I am using SQL Server 2017 on azure

Answer 2

Try this:

Declare @dt NVARCHAR(20)

Select 
    @dt = REPLACE(CONVERT(CHAR(15), SalesDate, 106),' ',' - ') 
FROM SalesTable

Answer 3

I Think this is the best way to do it.

REPLACE(CONVERT(NVARCHAR,CAST(WeekEnding AS DATETIME), 106), ' ', '-')

Because you do not have to use varchar(11) or varchar(10) that can make problem in future.

Answer 4

It doesn't look like DD-MMM-YYYY is supported by default (at least, with dash as separator). However, using the AS clause, you should be able to do something like:

SELECT CONVERT(VARCHAR(11), SYSDATETIME(), 106) AS [DD-MON-YYYY]

See here: http://www.sql-server-helper.com/sql-server-2008/sql-server-2008-date-format.aspx

Answer 5

SELECT Convert(varchar(10),CONVERT(date,'columnname',105),105) as "end";

OR

SELECT CONVERT(VARCHAR(10), CAST(event_enddate AS DATE), 105) AS [end];

will return the particular date in the format of 'dd-mm-yyyy'

The result would be like this..

04-07-2016

Answer 6

select CONVERT(NVARCHAR, SYSDATETIME(), 106) AS [DD-MON-YYYY]

or else

select REPLACE(CONVERT(NVARCHAR,GETDATE(), 106), ' ', '-')

both works fine