awk '{print $9}' the last ls -l column including any spaces in the file name

Question

How would I get awk to output the whole file name in ls -l if some of the files have spaces in them. Usually, I can run this command:

Answer 1

Just for completion. It can also be done with sed:

# just an exercise in regex matching ...
ls -l | sed -E  -e '1d; s/^([^ ]+ +){8}//'