How can I hash a string to an int using c++?

Question

I have to write my own hash function. If I wanted to just make the simple hash function that maps each letter in the string to a numerical value (i.e. a=1, b=2, c=3, ...), i

Answer 1

Re the first question, sure, e.g, something like:

int hash = 0;
int offset = 'a' - 1;
for(string::const_iterator it=s.begin(); it!=s.end(); ++it) {
  hash = hash << 1 | (*it - offset);
}

regarding the second, there are many better ways to hash strings. E.g., see here for a few C examples (easily translatable to C++ along the lines of the snippet above).

Answer 2

#include <iostream>
#include <string>
#include <algorithm>

using namespace std;

// a variation on dan bernstein's algorithm
// [http://www.cse.yorku.ca/~oz/hash.html]
template<typename Int>
struct hash {
    hash() : acc(5381) { }
    template<typename Ch>
    void operator()(Ch ch) { acc = ((acc << 5) + acc) ^ ch; }
    operator Int() const { return acc; }
    Int acc;
};

int main(int argc, char* argv[])
{
    string s("Hellp, world");
    cout << hex << showbase
        << for_each(s.begin(), s.end(), hash<unsigned long long>()) << '\n';
    return 0;
}

Answer 3

From personal experience I know that this works and produces good distributions. (Plagiarised from http://www.cse.yorku.ca/~oz/hash.html):

djb2

this algorithm (k=33) was first reported by dan bernstein many years ago in comp.lang.c. another version of this algorithm (now favored by bernstein) uses xor: hash(i) = hash(i - 1) * 33 ^ str[i]; the magic of number 33 (why it works better than many other constants, prime or not) has never been adequately explained.

unsigned long hash(unsigned char *str) {
    unsigned long hash = 5381;
    int c;

    while (c = *str++) {
        hash = ((hash << 5) + hash) + c; /* hash * 33 + c */
    }

    return hash;
}

Answer 4

You can make use of the member functions operator[] or at of the string class or iterators to access individual char of a string object without converting it to c-style char array.

To hash a string object to an integer you'll have to access each individual char of the string object which you can do as:

for (i=0; i < str.length(); i++) {
    // use str[i] or str.at(i) to access ith element.
}