Can I get the absolute path to the current script in KornShell?

Question

Is it possible to find out the full path to the script that is currently executing in KornShell (ksh)?

i.e. if my script is in /opt/scripts/myscript.ksh

Answer 1

Well it took me a while but this one is so simple it screams.

_SCRIPTDIR=$(cd $(dirname $0);echo $PWD)

since the CD operates in the spawned shell with $() it doesn't affect the current script.

Answer 2

In korn shell, all of these $0 solutions fail if you are sourcing in the script in question. The correct way to get what you want is to use $_

$ cat bar

echo dollar under is $_
echo dollar zero is $0

$ ./bar

dollar under is ./bar
dollar zero is ./bar

$ . ./bar
dollar under is bar
dollar zero is -ksh

Notice the last line there? Use $_. At least in Korn. YMMV in bash, csh, et al..

Answer 3

Try using this:

dir = $(dirname $0)

Answer 4

You could use:

## __SCRIPTNAME - name of the script without the path
##
typeset -r __SCRIPTNAME="${0##*/}"

## __SCRIPTDIR - path of the script (as entered by the user!)
##
__SCRIPTDIR="${0%/*}"

## __REAL_SCRIPTDIR - path of the script (real path, maybe a link)
##
__REAL_SCRIPTDIR=$( cd -P -- "$(dirname -- "$(command -v -- "$0")")" && pwd -P )

Answer 5

This works also, although it won't give the "true" path if it's a link. It's simpler, but less exact.

SCRIPT_PATH="$(whence ${0})"

Answer 6

Using $_ provides the last command.

>source my_script

Works if I issue the command twice:

>source my_script
>source my_script

If I use a different sequence of commands:

>who
>source my_script

The $_ variable returns "who"