Use query twice mysql_fetch_array

Question

a simple

$stuff = mysql_query(\"SELECT * FROM users\");

while($s = mysql_fetch_array($stuff)){
# ....
}

while($r = mysql_fetch_array($stuff)){
# ...
}


        

Answer 1

If you user "foreach" instead of "while" you'll not have any problem and no need to mysqli_seek_data() :

//1st loop :
foreach($stuff as $row)
{
   echo $row['...'];
}
...
//2nd loop :
foreach($stuff as $row)
{
   echo $row['...'];
}

Answer 2

Here is another simpler solution:

$slq = "SELECT * FROM users";

$stuff1 = mysql_query($slq);

while($s = mysql_fetch_array($stuff1)){
# ....
}

$stuff2 = mysql_query($slq);

while($r = mysql_fetch_array($stuff2)){
# ...
}

Assign the sql to a variable, and call mysql multiple times.

no more mysql. use mysqli or pdo

Answer 3

$stuff = mysql_query("SELECT * FROM users");

while($s = mysql_fetch_array($stuff)){
# ....
}
// add this line
mysql_data_seek( $stuff, 0 );

while($r = mysql_fetch_array($stuff)){
# ...
}

Should do the trick

Another way is of course to store your result in an array and reuse that

Answer 4

see the docs

I guess it's because

Returns an array that corresponds to the fetched row and moves the internal data pointer ahead.

I think moving data pointer with mysql_data_seek() would do the job But i think this is not a good way, you should usually fetch data from database once and store them

Answer 5

$stuff = mysql_query("SELECT * FROM users");

while($s = mysql_fetch_array($stuff)){
# ....
}
mysql_data_seek($stuff, 0);
while($r = mysql_fetch_array($stuff)){
# ...
}
//ref: http://www.php.net/manual/en/function.mysql-data-seek.php