I have a problem trying to remove a specific object from an array in Swift
Short Answer
you can find the index of object in array then remove it with index.
var array = [1, 2, 3, 4, 5, 6, 7]
var itemToRemove = 4
if let index = array.index(of: itemToRemove) {
array.remove(at: index)
}
Long Answer
if your array elements confirm to Hashable protocol you can use
array.index(of: itemToRemove)
because Swift can find the index by checking hashValue of array elements.
but if your elements doesn't confirm to Hashable protocol or you don't want find index base on hashValue then you should tell index method how to find the item. so you use index(where: ) instead which asks you to give a predicate clouser to find right element
// just a struct which doesn't confirm to Hashable
struct Item {
let value: Int
}
// item that needs to be removed from array
let itemToRemove = Item(value: 4)
// finding index using index(where:) method
if let index = array.index(where: { $0.value == itemToRemove.value }) {
// removing item
array.remove(at: index)
}
if you are using index(where:) method in lots of places you can define a predicate function and pass it to index(where:)
// predicate function for items
func itemPredicate(item: Item) -> Bool {
return item.value == itemToRemove.value
}
if let index = array.index(where: itemPredicate) {
array.remove(at: index)
}
for more info please read Apple's developer documents:
index(where:)
index(of:)
According to your code, the improvement could be like this:
if let index = arrPickerData.index(where: { $0.tag == pickerViewTag }) {
arrPickerData.remove(at: index)
//continue do: arrPickerData.append(...)
}
The index existing means Array contains the object with that Tag.
I used the solutions provided here: Remove Specific Array Element, Equal to String - Swift Ask Question
this is one of the solutions there (in case the object was a string):
myArrayOfStrings = ["Hello","Playground","World"]
myArrayOfStrings = myArrayOfStrings.filter{$0 != "Hello"}
print(myArrayOfStrings) // "[Playground, World]"