How to get the original request url from a servlet/jsp after multiple servlet forwards

Question

I am working on a cruise booking app using struts/tiles that uses multiple internal servlet/jsp forwards to reach the right jsp for display. But, once you r

Answer 1

I found a better answer in this post [ How do you detect the URL in a Java Servlet when forwarding to JSP? ]

On the target JSP use:

request.getAttribute("javax.servlet.forward.request_uri")

To find out what the original URL was.

It doesn't require you to take any extra steps on the forwarding servlet

Answer 2

You can show it without using a bean reference with the following:

<h:outputText value="#{requestScope['javax.servlet.forward.request_uri']}" />

Of course, you need to map the 404 page in your web.xml file though.

<error-page>
    <error-code>404</error-code>
    <location>/xhtml/pg/error/404.xhtml</location>
</error-page>

Answer 3

Consider using servlet filters instead to validate information. This means you can avoid your validation forwarding and just stay in a single JSP file.

Answer 4

${requestScope["javax.servlet.forward.request_uri"]}

or with single quotes

${requestScope['javax.servlet.forward.request_uri']}

Answer 5

You can use a filter to putting origin address to request attribute and then read it from jsp

Filter mapped to /booking/* execute:

request.setAttribute("origin", request.getRequestURL());

Jsp:

${pageContext.request.attribute["origin"]}

This works because filter has set REQUEST dispatcher by default. It means filter executes only for direct client requests not for forwarding/including

Answer 6

Same as @Lenny Markus but using the provided constant in the Request Dispatcher class.

request.getAttribute(RequestDispatcher.FORWARD_REQUEST_URI)