Open Settings App from another App in iOS - React Native

Question

I\'m going through the docs in React Native and can only find navigating to external links from the app I am in.

I want to be able to navigate to the Settings

Answer 1

I successfully opened the settings by the code below, hope it's helpful :)

Linking.canOpenURL('app-settings:').then(supported => {
  if (!supported) {
    console.log('Can\'t handle settings url');
  } else {
    return Linking.openURL('app-settings:');
  }
}).catch(err => console.error('An error occurred', err));

Reference: https://facebook.github.io/react-native//docs/linking.html

Answer 2

Since React Native version 0.59 this should be possible using openSettings();. This is described in the React Native Linking documentation. Although it did not work for me. When I tried quickly I saw a _reactNative.Linking.openSettings is not a function error message.

Linking.openSettings();

Answer 3

Linking.openURL('app-settings:1');

Answer 4

You can access settings of the application with: Linking.openURL('app-settings:');

But I don't know (yet) how to open a specific deep-link.

Answer 5

Adding an answer that worked for me and is easy to apply.

openSettings function in @react-native-community/react-native-permissions works for both iOS and Android.

Calling openSettings function will direct the user to the settings page of your app.

import { openSettings } from 'react-native-permissions';
openSettings();

Answer 6

You can import Linking from 'react-native' and then use Linking.openSettings() to trigger the call. This link explains it very concisely:

https://til.hashrocket.com/posts/eyegh79kqs-how-to-open-the-settings-app-in-reactnative-060