I\'m not sure if I\'m totally missing something here but I can\'t find any way to determine if a parameter is passed by reference or not by using reflection.
Argumen
if ref is parameterInfo.IsIn == true && parameterInfo.IsOut == true
then one might not need if parameterInfo.ParameterType.IsByRef
at all
ParameterInfo.ParameterType.IsByRef returns true if the declaration of the parameter is with the ByRef keyword, and returns false if the declaration is with the ByVal keyword (regardless of whether the type of the parameter is by-value (e.g., structure) or by-reference (e.g., class)).
To illustrate, consider the following structure and class (I'm using VB code):
' Empty structure and class, just for illustration.
Public Structure MyStruct
End Structure
Public Class MyClass1
End Class
And suppose you have the following method that takes ByVal and ByRef arguments for the structure and class defined above (note that starting with VB 2012, you can omit the ByVal keyword as it is the default):
Public Sub P(s1 As MyStruct, ByRef s2 As MyStruct, c1 As MyClass1, ByRef c2 As MyClass1)
End Sub
Now the following code tests the ParameterInfo.ParameterType.IsByRef method:
Private Sub Button1_Click(sender As System.Object, e As System.EventArgs) Handles Button1.Click
' Reflect on method P:
Dim mi As MethodInfo = Me.GetType.GetMethod("P")
' Iterate all parameters, and call its ParameterType.IsByRef method:
For Each pi As ParameterInfo In mi.GetParameters
If **pi.ParameterType.IsByRef** _
Then Console.WriteLine(pi.Name & " is ByRef") _
Else Console.WriteLine(pi.Name & " is ByVal")
Next
End Sub
You'll get the following output:
s1 is ByVal
s2 is ByRef
c1 is ByVal
c2 is ByRef
As you can see, ParameterInfo.ParameterType.IsByRef returns true for arguments s2 and c2 because they are defined with the ByRef keyword, even though one of them is a structure (value-type) and the other is a class (reference-type); and returns false for the arguments defined with the ByVal keyword.
Note, however, that the ByVal keyword does not mean that all arguments would be passed as a copy. Even if this keyword (ByVal) is used, if the type is by-reference (e.g., class), the argument would be passed by reference, as if the ByRef keyword were used. That is, c1 and c2 of method P above will BOTH be passed by reference, which means that if P changes a field or property to c1 or c2, the changes will be reflected to the caller. (ByVal and ByRef make difference mostly when the type is a value, such as a structure.)
You need to examine the type of your parameter further. For example if you have
void Foo(ref int bar)
then the name of the parameter wouldn't be int
or Int32
(as you might have expected) but instead Int32&
. For every type there is a correspondent by-ref-type where the original type is suffixed by a '&'.
You can check this via the IsByRef
property of the Type
class.
ParameterType.IsByRef
will return true
for both ref
and out
parameters.
If you have a ParameterInfo
object (e.g. from MethodInfo.GetParameters()
), then:
out
if parameterInfo.ParameterType.IsByRef && parameterInfo.IsOut
ref
if parameterInfo.ParameterType.IsByRef && parameterInfo.IsOut == false
If you don't do the IsByRef
check for out
parameters, then you'll incorrectly get members decorated with the [Out]
attribute from System.Runtime.InteropServices
but which aren't actually C# out
parameters.
ParameterInfo[] parameters = myMethodInfo.GetParameters();
foreach(ParameterInfo parameter in parameters)
{
bool isRef = parameterInfo.ParameterType.IsByRef;
}