If null use other variable in one line in PHP

Question

Is there in PHP something similar to JavaScript\'s:

alert(test || \'Hello\');

So, when test is undefined or null we\'ll see Hello, otherwis

Answer 1

alert((test == null || test == undefined)?'hello':test);

Answer 2

I recently had the very same problem.This is how i solved it:

<?php if (empty($row['test'])) {
                    echo "Not Provided";} 
                        else {
                    echo $row['test'];}?></h5></span></span>
              </div>

Your value in the database is in variable $test..so if $test row is empty then echo Not Provided

Answer 3

There may be a better way, but this is the first thing that came to my mind:

 echo (!$test) ? "Hello" : $test;

Answer 4

One-liner. Super readable, works for regular variables, arrays and objects.

// standard variable string
$result = @$var_str ?: "default";

// missing array element
$result = @$var_arr["missing"] ?: "default";

// missing object member
$result = @$var_obj->missing ?: "default";

See it in action: Php Sandbox Demo

Answer 5

See @Yamiko's answer below for a PHP7 solution https://stackoverflow.com/a/29217577/140413

 echo (!$test) ? 'hello' : $test;

Or you can be a little more robust and do this

echo isset($test) ? $test : 'hello'; 

Answer 6

Well, expanding that notation you supplied means you come up with:

if (test) {
    alert(test);
} else {
    alert('Hello');
}

So it's just a simple if...else construct. In PHP, you can shorten simple if...else constructs as something called a 'ternary expression':

alert($test ? $test : 'Hello');

Obviously there is no equivalent to the JS alert function in PHP, but the construct is the same.