I need to build a tcp frame with raw binary data, but all examples and tutorials I\'ve found talking about bytes always involve conversion from a string, and that\'s not wha
frame = b'\xa2\x01\x02\x03\x04'
wasn't mentionned till now...
I think Scapy is what are you looking for.
http://www.secdev.org/projects/scapy/
you can build and send frames (packets) with it
what about simply constructing your frame from a standard list ?
frame = bytes([0xA2,0x01,0x02,0x03,0x04])
the bytes()
constructor can build a byte frame from an iterable containing int
values. an iterable is anything which implements the iterator protocol: an list, an iterator, an iterable object like what is returned by range()
...
Here is a solution to getting an array (list) of bytes:
I found that you needed to convert the Int to a byte first, before passing it to the bytes():
bytes(int('0xA2', 16).to_bytes(1, "big"))
Then create a list from the bytes:
list(frame)
So your code should look like:
frame = b""
frame += bytes(int('0xA2', 16).to_bytes(1, "big"))
frame += bytes(int('0x01', 16).to_bytes(1, "big"))
frame += bytes(int('0x02', 16).to_bytes(1, "big"))
frame += bytes(int('0x03', 16).to_bytes(1, "big"))
frame += bytes(int('0x04', 16).to_bytes(1, "big"))
bytesList = list(frame)
The question was for an array (list) of bytes. You accepted an answer that doesn't tell how to get a list so I'm not sure if this is actually what you needed.
Use a bytearray:
>>> frame = bytearray()
>>> frame.append(0xA2)
>>> frame.append(0x01)
>>> frame.append(0x02)
>>> frame.append(0x03)
>>> frame.append(0x04)
>>> frame
bytearray(b'\xa2\x01\x02\x03\x04')
or, using your code but fixing the errors:
frame = b""
frame += b'\xA2'
frame += b'\x01'
frame += b'\x02'
frame += b'\x03'
frame += b'\x04'
agf's bytearray solution is workable, but if you find yourself needing to build up more complicated packets using datatypes other than bytes, you can try struct.pack()
. http://docs.python.org/release/3.1.3/library/struct.html