I am making a request like this:
fetch(\"https://api.parse.com/1/users\", {
method: \"GET\",
headers: headers,
body: body
})
How d
Just substitute values into the URL like this:
const encodedValue = encodeURIComponent(someVariable);
fetch(`https://example.com/foo?bar=${encodedValue}`);
Yes, you just need to add the query string to the URL yourself. You should take care to escape your query string parameters, though - don't just construct a URL like
`https://example.com/foo?bar=${someVariable}`
unless you're confident that someVariable
definitely doesn't contain any &
, =
, or other special characters.
If you were using fetch
outside of React Native, you'd have the option of encoding query string parameters using URLSearchParams. However, React Native does not support URLSearchParams. Instead, use encodeURIComponent.
For example:
const encodedValue = encodeURIComponent(someVariable);
fetch(`https://example.com/foo?bar=${encodedValue}`);
If you want to serialise an object of keys and values into a query string, you could make a utility function to do that:
function objToQueryString(obj) {
const keyValuePairs = [];
for (const key in obj) {
keyValuePairs.push(encodeURIComponent(key) + '=' + encodeURIComponent(obj[key]));
}
return keyValuePairs.join('&');
}
... and use it like this:
const queryString = objToQueryString({
key1: 'somevalue',
key2: someVariable,
});
fetch(`https://example.com/foo?${queryString}`);