How to split a string into only two parts, by the last occurrence of the split char?

Question

For example:

\"Angry Birds 2.4.1\".split(\" \", 2)
 => [\"Angry\", \"Birds 2.4.1\"] 

How can I split the string into: [\"Angry Bir

Answer 1

Something like this maybe ? Split where a space is followed by anything but a space till the end of the string.

"Angry Birds 2.4.1".split(/ (?=\S+$)/)
#=> ["Angry Birds", "2.4.1"]

Answer 2

reverse, split, then reverse every element and elements in array

"Angry Birds 2.4.1".reverse.split(' ', 2).map(&:reverse).reverse

Answer 3

String#rpartition, e.g.

irb(main):068:0> str = "Angry Birds 2.4.1"
=> "Angry Birds 2.4.1"
irb(main):069:0> str.rpartition(' ')
=> ["Angry Birds", " ", "2.4.1"]

Since the returned value is an array, using .first and .last would allow to treat the result as if it was split in two, e.g

irb(main):073:0> str.rpartition(' ').first
=> "Angry Birds"
irb(main):074:0> str.rpartition(' ').last
=> "2.4.1"

Answer 4

"Angry Birds 2.4.1".split(/ (?=\d+)/)