List Directories and get the name of the Directory

Question

I am trying to get the code to list all the directories in a folder, change directory into that folder and get the name of the current folder. The code I have so far is belo

Answer 1

import os
for root, dirs, files in os.walk(top, topdown=False):
    for name in dirs:
        print os.path.join(root, name)

Walk is a good built-in for what you are doing

Answer 2

Listing the entries in the current directory (for directories in os.listdir(os.getcwd()):) and then interpreting those entries as subdirectories of an entirely different directory (dir = os.path.join('/home/user/workspace', directories)) is one thing that looks fishy.

Answer 3

You seem to be using Python as if it were the shell. Whenever I've needed to do something like what you're doing, I've used os.walk()

For example, as explained here: [x[0] for x in os.walk(directory)] should give you all of the subdirectories, recursively.

Answer 4

This will print all the subdirectories of the current directory:

print [name for name in os.listdir(".") if os.path.isdir(name)]

I'm not sure what you're doing with split("-"), but perhaps this code will help you find a solution?

If you want the full pathnames of the directories, use abspath:

print [os.path.abspath(name) for name in os.listdir(".") if os.path.isdir(name)]

Note that these pieces of code will only get the immediate subdirectories. If you want sub-sub-directories and so on, you should use walk as others have suggested.