Is there a way for me to configure PyCharm to run shell_plus instead of the default shell?
I\'ve tried putting the text of the manage command in the \'Starting scr
One way to solve this is to create a new Python run configuration. Set the target to module, and select the manage.py
file for the project. Then put shell_plus
in the Parameters field. Set the Working Directory to the project directory. Then lastly, set the Execution to Run with Python Console
. Apply the changes, then run the new configuration.
In Django 1.7, following script can be used as a workaround with PyCharm 3.4:
File -> Settings -> Console -> Django Console and manage.py options
In Starting script
, put:
import sys
import django
django.setup()
from django.db.models import get_models
for _class in get_models():
globals()[_class.__name__] = _class
I got the model objects auto-loading by hooking into the shell_plus code. I appended this to the default startup script in Preferences > Build, Execution, Deployment > Console > Django Console
:
from django_extensions.management import shells
from django.core.management.color import color_style
imported_items = shells.import_objects({}, color_style())
for k, v in imported_items.items():
globals()[k] = v
This was on PyCharm 2018.3.3 Pro
For completeness, this was the full content of starting script:
import sys; print('Python %s on %s' % (sys.version, sys.platform))
import django; print('Django %s' % django.get_version())
sys.path.extend([WORKING_DIR_AND_PYTHON_PATHS])
if 'setup' in dir(django): django.setup()
import django_manage_shell; django_manage_shell.run(PROJECT_ROOT)
from django_extensions.management import shells
from django.core.management.color import color_style
imported_items = shells.import_objects({}, color_style())
for k, v in imported_items.items():
globals()[k] = v
I looked at the source code of shell_plus, and noticed you could use a method on a Command
class named get_imported_objects({})
In PyCharm, go to: Build, Execution, Deployment > Console > Django Console > Starting script
Add this to the existing code in that box:
from django_extensions.management.commands.shell_plus import Command
globals().update(Command().get_imported_objects({}))
As django.db.models.get_models
no longer exists, here's an updated version that will accomplish the same as Christopher Mason's version.
import sys; print('Python %s on %s' % (sys.version, sys.platform))
import django; print('Django %s' % django.get_version())
import logging
logging.basicConfig(format="%(levelname)-8s %(asctime)s %(name)s %(message)s", datefmt='%m/%d/%y %H:%M:%S', stream=sys.stdout )
log = logging.getLogger("root")
from django.apps import apps
from django.conf import settings
from django.core.exceptions import ObjectDoesNotExist, MultipleObjectsReturned
logging.config.dictConfig(settings.LOGGING)
log.debug("Logging has been initialized at DEBUG")
log.setLevel( logging.DEBUG)
log.disabled = False
for _configs in apps.get_app_configs():
for _class in _configs.get_models():
if _class.__name__.startswith("Historical"): continue
log.debug("Registering model {}".format(_class.__name__))
globals()[_class.__name__] = apps.get_model(_configs.label, _class.__name__)
def debug_sql():
from debug_toolbar.management.commands import debugsqlshell
return
This isn't a complete answer, but I found this script that at least loads up all the app models. Put this in Settings > Console > Django Console > Starting script:
import sys
import logging
logging.basicConfig(format="%(levelname)-8s %(asctime)s %(name)s %(message)s", datefmt='%m/%d/%y %H:%M:%S', stream=sys.stdout )
log = logging.getLogger("root")
from django.db.models import get_models
from django.conf import settings
from django.core.exceptions import ObjectDoesNotExist, MultipleObjectsReturned
logging.config.dictConfig(settings.LOGGING)
log.debug("Logging has been initialized at DEBUG")
log.setLevel( logging.DEBUG)
log.disabled = False
for _class in get_models():
if _class.__name__.startswith("Historical"): continue
log.debug("Registering model {}".format(_class.__name__))
globals()[_class.__name__] = _class
def debug_sql():
from debug_toolbar.management.commands import debugsqlshell
return
I also submitted this a feature request to JetBrains.