Byte array with padding of null bytes at the end: how to efficiently copy to smaller byte array

Question

Have:

[46][111][36][11][101][55][87][30][122][75][66][32][49][55][67][77][88][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0][0]


        

Answer 1

I think we can do in this way also

byte []array={0, 69, 0, 71, 0, 72};

byte ar[]=new String(array).replaceAll("\0", "").getBytes();

Answer 2

With kotlin :

val strWithoutZeros = String(byteArray,StandardCharsets.UTF_8).replace(0.toChar().toString(), "")

val byteArrayWithoutZeros = strWithoutZeros.toByteArray(StandardCharsets.UTF_8)

Answer 3

why not try the static method array copy in the system class just give the source array src start position , destination array , destination start position and the length

        System.arraycopy(src, srcPos, dest, destPos, length);
        byte [] dest= new byte [6000];
        System.arraycopy(src, 0, dest, 0, 6000);

Answer 4

Here is my try:

static byte[] trim(byte[] bytes)
{
    int i = bytes.length - 1;
    while (i >= 0 && bytes[i] == 0)
    {
        --i;
    }

    return Arrays.copyOf(bytes, i + 1);
}

public static void main(String[] args)
{
    byte[] bytes = { 0, 1, 2, 0, 3, 4, 5, 0, 6, 0, 0, 7, 8, 9, 10, 0, 0, 0, 0 };

    byte[] trimmed = trim(bytes);

    return;
}