Laravel active menu item for url included parameters

Question

I\'m trying to set active class in my list item, but it doesn\'t work.

My code in blade:

@foreach($data as $site)
  


        

Answer 1

Make a function in helper.

function activeMenu($uri = '') {
    $active = '';
    if (Request::is(Request::segment(1) . '/' . $uri . '/*') || Request::is(Request::segment(1) . '/' . $uri) || Request::is($uri)) {
        $active = 'active';
    }
    return $active;
}

Use it in sidebar.

<li class="{{ activeMenu('dashboard') }}"></li>
<li class="{{ activeMenu('student') }}"></li>
<li class="{{ activeMenu('teacher') }}"></li>

Answer 2

Use short if. Example:

<a href="#" class="{{ (\Request::route()->getName() == 'this.route') ? 'active' : '' }}">

Answer 3

I am currently using Laravel 5.6.* and my solution is:

<a href="#" class="nav-link {{ request()->is('users*') ? 'active' : '' }}">Users</a>

Answer 4

I am using Laravel 7 and Bootstrap Dropdown. So there are several collapse items that depend on the link, this works:

<li class="nav-item {{ Route::is('users.*') || Route::is('user.*')  ? 'active' : '' }}">

Answer 5

Use is() method. For example:

<li class="{{ request()->is('sites/*/edit') ? 'active' : '' }}"

Answer 6

Laravel 7+

For named routes with prefixes like admin or admin.view or admin.edit etc...

<li class="{{ Str::startsWith(Route::currentRouteName(), 'admin')) ? 'active' : '' }}">...</li>

A bit verbose but you can look into making a custom function like is_active('admin')