Date Time format in Flutter dd/MM/YYYY hh:mm

Question

By using this :

Text(new DateTime.fromMillisecondsSinceEpoch(values[index][\"start_time\"]*1000).toString(), 

I am getting the ty

Answer 1

You can use date_format plugin available here https://pub.dartlang.org/packages/date_format

Then to convert,

formatDate(DateTime.now(), [dd, '/', mm, '/', yyyy, ' ', HH, ':', nn])

Answer 2

var dateInFormatText = widget.snapshot["date"].toString().split("/");

DateTime dateResult = new DateTime.utc(
int.parse(dateInFormatText[2]),     
int.parse(dateInFormatText[1]), 
int.parse(dateInFormatText[0]));

Answer 3

If you use the intl package

final f = new DateFormat('yyyy-MM-dd hh:mm');

Text(f.format(new DateTime.fromMillisecondsSinceEpoch(values[index]["start_time"]*1000)));

Answer 4

If you use the intl package:

var date = DateTime.fromMicrosecondsSinceEpoch(miliseconds * 1000)
DateFormat(DateFormat.YEAR_MONTH_DAY, 'pt_Br').format(date.toUtc())

Output: 10 de abril de 2020

Answer 5

First install the pub.dev/packages/intl package in your pubspec.yaml

   intl: ^0.16.1

Then use

   final df = new DateFormat('dd-MM-yyyy hh:mm a');
   int myvalue = 1558432747;
   print(df.format(new DateTime.fromMillisecondsSinceEpoch(myvalue*1000)));

Output

21-05-2019 10:59 AM

Answer 6

Use intl package:

import 'package:intl/intl.dart';

And then:

var inputFormat = DateFormat('dd/MM/yyyy HH:mm');
var inputDate = inputFormat.parse('31/12/2000 23:59'); // <-- Incoming date

var outputFormat = DateFormat('MM/dd/yyyy hh:mm a');
var outputDate = outputFormat.format(inputDate); // <-- Desired date
print(outputDate); // 12/31/2000 11:59 PM