How to identify object types in java [duplicate]

Answer 1

Use value instanceof YourClass

Answer 2

You forgot the .class:

if (value.getClass() == Integer.class) {
    System.out.println("This is an Integer");
} 
else if (value.getClass() == String.class) {
    System.out.println("This is a String");
}
else if (value.getClass() == Float.class) {
    System.out.println("This is a Float");
}

Note that this kind of code is usually the sign of a poor OO design.

Also note that comparing the class of an object with a class and using instanceof is not the same thing. For example:

"foo".getClass() == Object.class

is false, whereas

"foo" instanceof Object

is true.

Whether one or the other must be used depends on your requirements.

Answer 3

You can compare class tokens to each other, so you could use value.getClass() == Integer.class. However, the simpler and more canonical way is to use instanceof :

    if (value instanceof Integer) {
        System.out.println("This is an Integer");
    } else if(value instanceof String) {
        System.out.println("This is a String");
    } else if(value instanceof Float) {
        System.out.println("This is a Float");
    }

Notes:

• the only difference between the two is that comparing class tokens detects exact matches only, while instanceof C matches for subclasses of C too. However, in this case all the classes listed are final, so they have no subclasses. Thus instanceof is probably fine here.

• as JB Nizet stated, such checks are not OO design. You may be able to solve this problem in a more OO way, e.g.

  System.out.println("This is a(n) " + value.getClass().getSimpleName());
  

Answer 4

You want instanceof:

if (value instanceof Integer)

This will be true even for subclasses, which is usually what you want, and it is also null-safe. If you really need the exact same class, you could do

if (value.getClass() == Integer.class)

or

if (Integer.class.equals(value.getClass())