I am trying to change the color of the function swapFE() below and I can\'t figure out how to write it. I was told to change the color of the phrase node to the color value
dec2hex = function (d) {
if (d > 15)
{ return d.toString(16) } else
{ return "0" + d.toString(16) }
}
rgb = function (r, g, b) { return "#" + dec2hex(r) + dec2hex(g) + dec2hex(b) };
and:
parent.childNodes[1].style.color = rgb(155, 102, 102);
try:
parent.childNodes[1].style.color = "rgb(155, 102, 102)";
Or
parent.childNodes[1].style.color = "#"+(155).toString(16)+(102).toString(16)+(102).toString(16);
Here's a simple function that creates a CSS color string from RGB values ranging from 0 to 255:
function rgb(r, g, b){
return "rgb("+r+","+g+","+b+")";
}
Alternatively (to create fewer string objects), you could use array join():
function rgb(r, g, b){
return ["rgb(",r,",",g,",",b,")"].join("");
}
The above functions will only work properly if (r, g, and b) are integers between 0 and 255. If they are not integers, the color system will treat them as in the range from 0 to 1. To account for non-integer numbers, use the following:
function rgb(r, g, b){
r = Math.floor(r);
g = Math.floor(g);
b = Math.floor(b);
return ["rgb(",r,",",g,",",b,")"].join("");
}
You could also use ES6 language features:
const rgb = (r, g, b) =>
`rgb(${Math.floor(r)},${Math.floor(g)},${Math.floor(b)})`;
I am showing with an example of adding random color. You can write this way
var r = Math.floor(Math.random() * 255);
var g = Math.floor(Math.random() * 255);
var b = Math.floor(Math.random() * 255);
var col = "rgb(" + r + "," + g + "," + b + ")";
parent.childNodes[1].style.color = col;
The property is expected as a string
ES6 (template literal) helper functions:
function rgba(r, g, b, a=1){
return `rgba(${r}, ${g}, ${b}, ${a})`
}
function rgb(r, g, b){
return `rgb(${r}, ${g}, ${b})`
}
this is better function
function RGB2HTML(red, green, blue)
{
var decColor =0x1000000+ blue + 0x100 * green + 0x10000 *red ;
return '#'+decColor.toString(16).substr(1);
}