I am framing a regex to check if a word starts with http://
or https://
or ftp://
, my code is as follows,
public
test.matches() method checks all text.use test.find()
You need a whole input match here.
System.out.println(test.matches("^(http|https|ftp)://.*$"));
Edit:(Based on @davidchambers's comment)
System.out.println(test.matches("^(https?|ftp)://.*$"));
If you wanna do it in case-insensitive way, this is better:
System.out.println(test.matches("^(?i)(https?|ftp)://.*$"));
Unless there is some compelling reason to use a regex, I would just use String.startsWith:
bool matches = test.startsWith("http://")
|| test.startsWith("https://")
|| test.startsWith("ftp://");
I wouldn't be surprised if this is faster, too.
I think the regex / string parsing solutions are great, but for this particular context, it seems like it would make sense just to use java's url parser:
https://docs.oracle.com/javase/tutorial/networking/urls/urlInfo.html
Taken from that page:
import java.net.*;
import java.io.*;
public class ParseURL {
public static void main(String[] args) throws Exception {
URL aURL = new URL("http://example.com:80/docs/books/tutorial"
+ "/index.html?name=networking#DOWNLOADING");
System.out.println("protocol = " + aURL.getProtocol());
System.out.println("authority = " + aURL.getAuthority());
System.out.println("host = " + aURL.getHost());
System.out.println("port = " + aURL.getPort());
System.out.println("path = " + aURL.getPath());
System.out.println("query = " + aURL.getQuery());
System.out.println("filename = " + aURL.getFile());
System.out.println("ref = " + aURL.getRef());
}
}
yields the following:
protocol = http
authority = example.com:80
host = example.com
port = 80
path = /docs/books/tutorial/index.html
query = name=networking
filename = /docs/books/tutorial/index.html?name=networking
ref = DOWNLOADING