Extract the last directory of a pwd output

Question

How do I extract the last directory of a pwd output? I don\'t want to use any knowledge of how many levels there are in the directory structure. If I wanted to use that, I c

Answer 1

Are you looking for basename or dirname?

Something like

basename "`pwd`"

should be what you want to know.

If you insist on using sed, you could also use

pwd | sed 's#.*/##'

Answer 2

Should work for you: pwd | rev | cut -f1 -d'/' - | rev

Reference: https://stackoverflow.com/a/31728689/663058

Answer 3

Using awk:

pwd | awk -F/ '{print $NF}'

Answer 4

If you want to do it completely within a bash script without running any external binaries, ${PWD##*/} should work.