How to convert dictionary to array

Question

I want to convert my dictionary to an array, by showing each [String : Int] of the dictionary as a string in the array.

For example:     

Answer 1

The general case for creating an array out of ONLY VALUES of a dictionary in Swift 3 is (I assume it also works in older versions of swift):

let arrayFromDic = Array(dic.values.map{ $0 })

Example:

let dic = ["1":"a", "2":"b","3":"c"]

let ps = Array(dic.values.map{ $0 })

print("\(ps)")

for p in ps {
    print("\(p)")
}

Answer 2

If you like concise code and prefer a functional approach, you can use the map method executed on the keys collection:

let array = Array(myDict.keys.map { "\($0) \(myDict[$0]!)" })

or, as suggested by @vacawama:

let array = myDict.keys.array.map { "\($0) \(myDict[$0]!)" }

which is functionally equivalent

Answer 3

With Swift 5

var myDict:[String : Int] = ["attack" : 1, "defend" : 5, "block" : 12]

let arrayValues = myDict.values.map({$0})
let arrayKeys = myDict.keys.map({$0})

Answer 4

You will have to go through and construct a new array yourself from the keys and the values.

Have a look at 's swift array documentation:

You can add a new item to the end of an array by calling the array’s append(_:) method:

Try this:

var myDict:[String : Int] = ["attack" : 1, "defend" : 5, "block" : 12]

var dictArray: [String] = []

for (k, v) in myDict {
    dictArray.append("\(k) \(v)")
}

Have a look at What's the cleanest way of applying map() to a dictionary in Swift? if you're using Swift 2.0:

Answer 5

You can use a for loop to iterate through the dictionary key/value pairs to construct your array:

var myDict: [String : Int] = ["attack" : 1, "defend" : 5, "block" : 12]

var arr = [String]()

for (key, value) in myDict {
    arr.append("\(key) \(value)")
}

Note: Dictionaries are unordered, so the order of your array might not be what you expect.

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In Swift 2 and later, this also can be done with map:

let arr = myDict.map { "\($0) \($1)" }

This can also be written as:

let arr = myDict.map { "\($0.key) \($0.value)" }

which is clearer if not as short.