How to remove an element of a given value from an array in Swift

Question

I want to remove all elements of value x from an array that contains x, y and z elements

let arr = [\'a\', \'b\', \'c\', \'b\']

How can I r

Answer 1

EDITED according to comments:

I like this approach:

var arr = ["a", "b", "c", "b"]

while let idx = arr.index(of:"b") {
    arr.remove(at: idx)
}

Original answer (before editing):

let arr = ['a', 'b', 'c', 'b']

if let idx = arr.index(of:"b") {
    arr.remove(at: idx)
}

Answer 2

In Swift 3 I simply do:

arr = arr.filter { $0 != "a" } 

.filter, .sort and .map are great for saving time and solve lots of problems with little code.

This article has good examples and explain the differences and how they work: https://useyourloaf.com/blog/swift-guide-to-map-filter-reduce/

Answer 3

If you need to modify initial array, you can use the function removeAll(where:) that is available in Swift 4.2/Xcode 10:

var arr = ["a", "b", "c", "b"]
arr.removeAll(where: { $0 == "b" })
print(arr) // output is ["a", "c"]

However, if you are using Xcode 9 you can find this function in Xcode9to10Preparation (this library provides implementations of some new functions from Xcode 10).

Answer 4

If you have more than one element to remove, thanks to first answer.

 var mainArray = ["a", "b", "qw", "qe"]
 let thingsToRemoveArray = ["qw", "b"] 


        for k in thingsToRemoveArray {
            mainArray =  mainArray.filter {$0 != k}
          }

Answer 5

var array : [String]
array = ["one","two","one"]

let itemToRemove = "one"

while array.contains(itemToRemove) {
    if let itemToRemoveIndex = array.index(of: itemToRemove) {
        array.remove(at: itemToRemoveIndex)
    }
}

print(array)

Works on Swift 3.0.

Answer 6

A filter:

 let farray = arr.filter {$0 != "b"}