I love vinepeek and want to make something better.
I have the Vine link e.g. http://vine.co/v/bJqWrOHjMmU
, however this is a link to a page, not the vid
The JSON API has the following URL: http://vinepeek.com/video
You can use a web inspector / console / developer tool to check the source code.
<video id="post_html5_api" class="vjs-tech" loop="" preload="auto" src="https://vines.s3.amazonaws.com/videos/08C49094-DFB4-46DF-8110-EEEC7D4D6115-1133-000000B8AD9BE72C_1.0.1.mp4?versionId=TQGtC5O7G7H34TleFA2LF0Er9tI8VZUe"></video>
The URL is:
https://vines.s3.amazonaws.com/videos/08C49094-DFB4-46DF-8110-EEEC7D4D6115-1133-000000B8AD9BE72C_1.0.1.mp4?versionId=TQGtC5O7G7H34TleFA2LF0Er9tI8VZUe
It is in the page source; you could parse it with a JavaScript bookmarklet
function qry(sr) {
var qa = [];
for (var prs of sr.split('&')) {
var pra = prs.split('=');
qa[pra[0]] = pra[1];
}
return qa;
}
var alpha = document.querySelector('[name=flashvars]').getAttribute('value');
var bravo = qry(alpha);
bravo.src;
Result
https://vines.s3.amazonaws.com/videos/08C49094-DFB4-46DF-8110-EEEC7D4D6115-1133-000000B8AD9BE72C_1.0.1.mp4?versionId=TQGtC5O7G7H34TleFA2LF0Er9tI8VZUe
Source
This is a simple function which i use to get video src from curl result. http://vine.co/v/bJqWrOHjMmU
function getVineVideoFromUrl($url) {
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$res = curl_exec($ch);
preg_match('/twitter:player:stream.*content="(.*)"/', $res, $output);
return $output[1];
}
result
https://vines.s3.amazonaws.com/v/videos/08C49094-DFB4-46DF-8110-EEEC7D4D6115-1133-000000B8AD9BE72C_1.0.1.mp4?versionId=ms6ePoPeFm6NQZkeNHegV3k_ZLV4bz9x