I want to simulate a tree
command using Shell Script that displays all the directories recursively in this format:
.
|-- Lorem
|-- Lorem
|-- Lor
Modifying sputnick's answer to get closer to your original format (which I prefer):
find ./ -type d -print | sed -e 's;[^/]*/; /;g;s;/ ; ;g;s;^ /$;.;;s; /;|-- ;g'
The only difference now is the last line doesn't start with a backtick:
.
|-- Lorem
|-- Lorem
|-- Lorem
|-- Lorem
|-- Lorem
|-- Lorem
|-- Lorem
find . -type d -print 2>/dev/null | awk '!/\.$/ {for (i=1;i<NF-1;i++){printf(" ")}printf("|-- ")};{print $NF}' FS='/'
ls -R | grep ":$" | sed -e 's/:$//' -e 's/[^-][^/]*//--/g' -e 's/^/ /' -e 's/-/|/'
taken from here: http://www.centerkey.com/tree/
You can just launch :
tree .
OR
tree $absolute/path/of/your/dir
If you want to display the hidden files.
By default tree does not print hidden files (those beginning with a dot '.'), just type:
tree -a .
This is what tree command do.
Modified base on the awk one from http://www.unix.com/shell-programming-scripting/50806-directory-tree.html
pwd;find . -type d -print 2>/dev/null|awk '!/\.$/ {for (i=1;i<NF-1;i++){printf("│ ")}print "├── "$NF}' FS='/'
Output looks more similar to tree
:
/etc
├── sudoers.d
├── susehelp.d
│ ├── htdig
├── sysconfig
│ ├── SuSEfirewall2.d
│ │ ├── services
│ ├── network
│ │ ├── if-down.d
│ │ ├── if-up.d
│ │ ├── providers
│ │ ├── scripts
│ ├── scripts
├── sysctl.d
├── systemd
│ ├── system
│ │ ├── default.target.wants
│ │ ├── getty.target.wants
│ │ ├── multi-user.target.wants
Try doing this (not exactly the same output, but very close) :
find ./ -type d -print | sed -e 's;[^/]*/;|____;g;s;____|; |;g'
From http://mlsamuelson.com/content/tree-approximation-using-find-and-sed
find . -type d -print 2>/dev/null|awk '!/\.$/ {for (i=1;i<NF;i++){d=length($i);if ( d < 5 && i != 1 )d=5;printf("%"d"s","|")}print "---"$NF}' FS='/'
See http://www.unix.com/shell-programming-scripting/50806-directory-tree.html