Deploy Flask app as windows service

Question

I\'m using the template found here: Is it possible to run a Python script as a service in Windows? If possible, how?

Here\'s my run.py, which i\'ve installed as a se

Answer 1

I appended my code in SvcStop() last line. "self.ReportServiceStatus(win32service.SERVICE_STOPPED)"

In my case, It's works for stopping service.

from app import app

import win32serviceutil
import win32service
import win32event
import servicemanager
import socket


class AppServerSvc (win32serviceutil.ServiceFramework):
    _svc_name_ = "Flask App"
    _svc_display_name_ = "Flask App"

    def __init__(self,args):
        win32serviceutil.ServiceFramework.__init__(self,args)
        self.hWaitStop = win32event.CreateEvent(None,0,0,None)
        socket.setdefaulttimeout(60)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)
        # !important! to report "SERVICE_STOPPED"
        self.ReportServiceStatus(win32service.SERVICE_STOPPED)

    def SvcDoRun(self):
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
                              servicemanager.PYS_SERVICE_STARTED,
                              (self._svc_name_,''))
        self.main()

    def main(self):
        app.run(host = '192.168.1.6')

if __name__ == '__main__':
    win32serviceutil.HandleCommandLine(AppServerSvc)

Answer 2

I can't access WSGIRequestHandler in Flask outside request, so I use Process.

import win32serviceutil
import win32service
import win32event
import servicemanager
from multiprocessing import Process

from app import app


class Service(win32serviceutil.ServiceFramework):
    _svc_name_ = "TestService"
    _svc_display_name_ = "Test Service"
    _svc_description_ = "Tests Python service framework by receiving and echoing messages over a named pipe"

    def __init__(self, *args):
        super().__init__(*args)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        self.process.terminate()
        self.ReportServiceStatus(win32service.SERVICE_STOPPED)

    def SvcDoRun(self):
        self.process = Process(target=self.main)
        self.process.start()
        self.process.run()

    def main(self):
        app.run()


if __name__ == '__main__':
    win32serviceutil.HandleCommandLine(Service)

Answer 3

Figured it out--I'd left the debug option on in the app.run(). Once i removed that, it's good to go!

While the service starts and runs correctly (I can access my flask app from another computer on the network), it is unable to stop. In the thread with the posted template i used, the author mentions something about setting a flag to properly stop the service.

Anyone know what he means by this and how to code it to properly stop the service?