Generate random colors (RGB)

Question

I just picked up image processing in python this past week at the suggestion of a friend to generate patterns of random colors. I found this piece of script online that gene

Answer 1

A neat way to generate RGB triplets within the 256 (aka 8-byte) range is

color = list(np.random.choice(range(256), size=3))

color is now a list of size 3 with values in the range 0-255. You can save it in a list to record if the color has been generated before or no.

Answer 2

Here:

def random_color():
    rgbl=[255,0,0]
    random.shuffle(rgbl)
    return tuple(rgbl)

The result is either red, green or blue. The method is not applicable to other sets of colors though, where you'd have to build a list of all the colors you want to choose from and then use random.choice to pick one at random.

Answer 3

color = lambda : [random.randint(0, 255), random.randint(0, 255), random.randint(0, 255)]

Answer 4

You could also use Hex Color Code,

Name    Hex Color Code  RGB Color Code
Red     #FF0000         rgb(255, 0, 0)
Maroon  #800000         rgb(128, 0, 0)
Yellow  #FFFF00         rgb(255, 255, 0)
Olive   #808000         rgb(128, 128, 0)

For example

import matplotlib.pyplot as plt
import random

number_of_colors = 8

color = ["#"+''.join([random.choice('0123456789ABCDEF') for j in range(6)])
             for i in range(number_of_colors)]
print(color)

['#C7980A', '#F4651F', '#82D8A7', '#CC3A05', '#575E76', '#156943', '#0BD055', '#ACD338']

Lets try plotting them in a scatter plot

for i in range(number_of_colors):
    plt.scatter(random.randint(0, 10), random.randint(0,10), c=color[i], s=200)

plt.show()

Answer 5

Inspired by other answers this is more correct code that produces integer 0-255 values and appends alpha=255 if you need RGBA:

tuple(np.random.randint(256, size=3)) + (255,)

If you just need RGB:

tuple(np.random.randint(256, size=3))

Answer 6

import random
rgb_full="(" + str(random.randint(1,256))  + "," + str(random.randint(1,256))  + "," + str(random.randint(1,256))  + ")"