I have one entity in room
@Entity(foreignKeys ={
@ForeignKey(entity = Label.class, parentColumns = \"_id\", childColumns = \"labelId\", onDelete = CA
If you wonder to make a single column to be unique, only need to write
@Entity(indices = [Index(value = ["name"], unique = true)])
For a single column Uniqueness
@Entity(indices = {@Index(value = {"first_name"},unique = true)})
For Multiple column Uniqueness
@Entity(indices = {@Index(value = {"first_name", "last_name"},unique = true)})
A plain UNIQUE constraint on a column, other than via an index, is not supported.
You can enforce this uniqueness property by setting the unique property of an @Index annotation to true. The following code sample (Java) prevents a table from having two rows that contain the same set of values for the firstName and lastName columns:
@Entity(indices = {@Index(value = {"first_name", "last_name"},
unique = true)})
class User {
@PrimaryKey
public int id;
@ColumnInfo(name = "first_name")
public String firstName;
@ColumnInfo(name = "last_name")
public String lastName;
@Ignore
Bitmap picture;
}
The Kotlin equivalent of the annotation is given below:
@Entity(indices = arrayOf(Index(value = ["first_name", "last_name"], unique = true)))
In your code you can do the following changes to have UNIQUE constraints
@Entity(foreignKeys ={
@ForeignKey(entity = Label.class, parentColumns = "_id", childColumns = "labelId", onDelete = CASCADE),
@ForeignKey(entity = Task.class, parentColumns = "_id", childColumns = "taskId", onDelete = CASCADE)},
indices = {@Index(value = {"labelId", "taskId"},
unique = true)}
)
public class LabelOfTask extends Data{
@ColumnInfo(name = "labelId")
private Integer labelId;
@ColumnInfo(name = "taskId")
private Integer taskId;
}