Multiple Flags for json_encode()

Question

How do I use multiple flags for the php json_encode()-function?

json_encode($array, JSON_PRETTY_PRINT, JSON_UNESCAPED_UNICODE);

This doesn\

Answer 1

Those flags are bitmasks. I wrote about it once a long time ago here on SO.

So, basically, to use more than one option, you need to or them together

json_encode($array, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE);

Answer 2

You use a bitmask, as specified in http://php.net/manual/en/function.json-encode.php:

json_encode($array, JSON_PRETTY_PRINT|JSON_UNESCAPED_UNICODE);

This will add the binary values of JSON_PRETTY_PRINT and JSON_UNESCAPED_UNICODE with the binary OR operator.