Set $_SERVER variable when calling PHP from command line?

Question

Is it possible to pass a $_SERVER variable to a PHP script via the command line?

Specifically I am trying to set the $_SERVER[\'recipient\'] manually so I can test e

Answer 1

You can also pass two and more variables. For example:

$ SERVER_NAME="example.com" REQUEST_URI="?foo=bar" php script.php

<?php

print_r($_SERVER);

Answer 2

How about setting up a dummy page called dummy.php with this contents:

<?php
    $_SERVER['recipient'] = 'me@gmail.com';
?>

Answer 3

On *nix:

$ recipient="email@domain.com" php script.php

<?php

print_r($_SERVER);

Test:

$ recipient="email@domain.com" php script.php | grep recipient

[recipient] => something@domain.com

Or, you can export it or setenv (depending on your OS), like

$ export recipient="email@domain.com"
$ setenv recipient="email@domain.com"

Answer 4

I personally use the following.

Example: set $_SERVER['recipient] in my PHP command line.

With OS X

• Follow the instructions in https://github.com/ersiner/osx-env-sync

• Append the following line to the file '~/.bash_profile' (create it, if it does not exist)

  export recipient="something@example.com"

With Ubuntu GNU/Linux

• Append the following line to the file '/etc/environment' (create it, if it does not exist, see https://help.ubuntu.com/community/EnvironmentVariables)

  recipient=something@example.com

Answer 5

The answer by @sberry is correct.

...but because I came to this page looking for setting default values for the $_SERVER array, when running PHP from command line, here is my own answer. Hope it might help somebody.

empty( $_SERVER['HTTP_HOST'] ) && $_SERVER['HTTP_HOST'] = 'localhost';
empty( $_SERVER['REQUEST_URI'] ) && $_SERVER['REQUEST_URI'] = '/';
empty( $_SERVER['DOCUMENT_ROOT'] ) && $_SERVER['DOCUMENT_ROOT'] = __DIR__;
print_r( $_SERVER );