Python/Django: Creating a simpler list from values_list()

Question

Consider:

>>>jr.operators.values_list(\'id\')
[(1,), (2,), (3,)]

How does one simplify further to:

[\'1\', \'2\',          


        

Answer 1

Something like this?

x = [(1,), (2,), (3,)]
y = [str(i[0]) for i in x]
['1', '2', '3']

Answer 2

You need to do ..to get this output ['1', '2', '3']

map(str, Entry.objects.values_list('id', flat=True).order_by('id'))

Answer 3

You can use a list comprehension:

    >>> mylist = [(1,), (2,), (3,)]
    >>> [str(x[0]) for x in mylist]
    ['1', '2', '3']

Answer 4

Use the flat=True construct of the django queryset: https://docs.djangoproject.com/en/dev/ref/models/querysets/#django.db.models.query.QuerySet.values_list

From the example in the docs:

>>> Entry.objects.values_list('id', flat=True).order_by('id')
[1, 2, 3, ...]