What is std::invoke in c++? [closed]

Answer 1

A Callable object is, apart from C++-specific details, "something that can be called". It need not be a function: C++ has a number of types that can be called, and going through them every time where any could show up (read: generic code) is problematic and too repetitive.

That's what std::invoke is for - it allows a generic object that can be called (which, according to C++17, satisfies the Callable concept) to be invoked effortlessly.

Let's consider a simple example:

void foo() { std::cout << "hello world\n"; };

template <bool b>
struct optionally_callable
{
        std::enable_if_t<b> operator() ()  {   std::cout << "hi again\n";   }
};

int main()
{
    auto c = [] { std::cout << "hi from lambda\n" ;};

    std::invoke(foo);
    std::invoke(c);

    auto o = optionally_callable<true>{};
    //auto o2 = optionally_callable<false>{};

    std::invoke(o);

}

o2 is not callable, that is, std::is_invocable<decltype(o2)>::value is false.

Answer 2

std::invoke takes something callable, and arguments to call it with, and does the call. std::invoke( f, args... ) is a slight generalization of typing f(args...) that also handles a few additional cases.

Something callable includes a function pointer or reference, a member function pointer, an object with an operator(), or a pointer to member data.

In the member cases, the first argument is interpreted as the this. Then remaining arguments are passed to () (except in the pointer-to-member-data-case), with std::reference_wrappers unwrapping.

INVOKE was a concept in the C++ standard; C++17 simply exposed a std::invoke which does it directly. I suspect it was exposed partly because it is useful when doing other metaprogramming, partly because every standard library has an implementation of INVOKE in it already and exposing it was basically free, and partly because it makes talking about INVOKE easier when it is a concrete thing.