I can check for a next()
method, but is that enough? Is there an ideomatic way?
There is a better method than other answers have suggested.
In Python we have two kinds of things: Iterable
and Iterator
. An object is Iterable
if it can give you Iterator
. It does so when you use iter()
on it. An object is Iterator
if you can use next()
to sequentially browse through its elements. For example, map()
returns Iterator
and list
is Iterable
.
Here are more details.
Below code illustrates how to check for these types:
from collections.abc import Iterable, Iterator
r = [1, 2, 3]
e = map(lambda x:x, r)
print(isinstance(r, Iterator)) # False, because can't apply next
print(isinstance(e, Iterator)) # True
print(isinstance(r, Iterable)) # True, because can apply iter()
print(isinstance(e, Iterable)) # True, note iter() returns self
To be an iterator an object must pass three tests:
obj
has an __iter__
methodobj
has a next
method (or __next__
in Python 3)obj.__iter__()
returns obj
So, a roll-your-own test would look like:
def is_iterator(obj):
if (
hasattr(obj, '__iter__') and
hasattr(obj, 'next') and # or __next__ in Python 3
callable(obj.__iter__) and
obj.__iter__() is obj
):
return True
else:
return False
answer from python sourcecode doc comments:
{python install path}/Versions/3.5/lib/python3.5/types.py
# Iterators in Python aren't a matter of type but of protocol. A large
# and changing number of builtin types implement *some* flavor of
# iterator. Don't check the type! Use hasattr to check for both
# "__iter__" and "__next__" attributes instead.
An object is iterable if it implements the iterator protocol.
You could check the presence of __iter__()
method with:
hasattr(object,'__iter__')
in Python 2.x this approach misses str objects and other built-in sequence types like unicode, xrange, buffer. It works in Python 3.
Another way is to test it with iter method :
try:
iter(object)
except TypeError:
#not iterable
from collections.abc import Iterator
isinstance(object, Iterator)
As the question is about Iterator not Iterable and considering usage of iterator, a simplest and pythonic way of doing this
iterable = [1,2]
iterator = iter(iterable)
def isIterator(obj):
try:
next(obj, None)
return True
except TypeError:
return False
>>> isIterator(iterable)
False
>>> isIterator(iterator)
True
Yes. Checking on next() should be enough