remove url parameters with javascript or jquery

Question

I am trying to use the youtube data api to generate a video playlist.

However, the video urls require a format of:

youtube.com/watch?v=3sZOD3xKL0Y
<         


        

Answer 1

Use this function:

var getCleanUrl = function(url) {
  return url.replace(/#.*$/, '').replace(/\?.*$/, '');
};

// get rid of hash and params
console.log(getCleanUrl('https://sidanmor.com/?firstname=idan&lastname=mor'));

If you want all the href parts, use this:

var url = document.createElement('a');
url.href = 'https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container';

console.log(url.href); // https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container
console.log(url.protocol); // https:
console.log(url.host); // developer.mozilla.org
console.log(url.hostname); // developer.mozilla.org
console.log(url.port); // (blank - https assumes port 443)
console.log(url.pathname); // /en-US/search
console.log(url.search); // ?q=URL
console.log(url.hash); // #search-results-close-container
console.log(url.origin); // https://developer.mozilla.org

Answer 2

//user113716 code is working but i altered as below. it will work if your URL contain "?" mark or not
//replace URL in browser
if(window.location.href.indexOf("?") > -1) {
    var newUrl = refineUrl();
    window.history.pushState("object or string", "Title", "/"+newUrl );
}

function refineUrl()
{
    //get full url
    var url = window.location.href;
    //get url after/  
    var value = url = url.slice( 0, url.indexOf('?') );
    //get the part after before ?
    value  = value.replace('@System.Web.Configuration.WebConfigurationManager.AppSettings["BaseURL"]','');  
    return value;     
}

Answer 3

What am I missing?

Why not:

url.split('?')[0] 

Answer 4

Example: http://jsfiddle.net/SjrqF/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.slice( 0, url.indexOf('&') );

or:

Example: http://jsfiddle.net/SjrqF/1/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.split( '&' )[0];