C# to Java - Dictionaries?

Question

Is it possible in Java to make a Dictionary with the items already declared inside it? Just like the below C# code:

   Dictionary d = new          


        

Answer 1

Java7 almost introduced "collection literals" that would allow syntax like that. They'll probably try to shove it in Java8. I have no idea what is wrong with these people.

This can be easily achieved by some kind of wrapper API

Map<String,Integer> map = Maps.<String,Integer>empty()
    .put("cat", 2).put("dog",1)....; 

Not too bad. I would prefer something like

map("cat", "dog", ... )
.to(  1,     2,   ... );

This kind of thing must have been implemented by various people, unfortunately the standard API doesn't inculde such things.

Answer 2

If you use the Guava library, you can use its ImmutableMap class, either by itself (examples 1 and 2), or as an initializer for a HashMap (examples 3 and 4):

Map<String, Integer> map1 = ImmutableMap.<String, Integer> builder()
    .put("cat", 2)
    .put("dog", 1)
    .put("llama", 0)
    .put("iguana", -1)
    .build();
Map<String, Integer> map2 = ImmutableMap.of(
    "cat", 2,
    "dog", 1,
    "llama", 0,
    "iguana", -1
);
Map<String, Integer> map3 = Maps.newHashMap(
    ImmutableMap.<String, Integer> builder()
    .put("cat", 2)
    .put("dog", 1)
    .put("llama", 0)
    .put("iguana", -1)
    .build()
);
Map<String, Integer> map4 = Maps.newHashMap( ImmutableMap.of(
    "cat", 2,
    "dog", 1,
    "llama", 0,
    "iguana", -1)
);

Answer 3

Bite the bullet and type out the map name!

    Map<String, Integer> map = new HashMap<String, Integer>();
    map.put("cat", 2);
    map.put("dog", 1);
    map.put("llama", 0);
    map.put("iguana", -1);

You could also do something like this, which might save some typing with a long list:

    Object[][] values = {
        {"cat", 2},
        {"dog", 1},
        {"llama", 0},
        {"iguana", -1}
    };

    for (Object[] o : values) {
        map.put((String) o[0], (Integer) o[1]);
    }

Answer 4

This will do what you want:

Map<String,Integer> map = new HashMap<String, Integer>(){{
    put("cat", 2);
    put("dog", 1);
    put("llama", 0);
    put("iguana", -1);
}};

This statement creates an anonymous subclass of HashMap, where the only difference from the parent class is that the 4 entries are added during instance creation. It's a fairly common idiom in the Java world (although some find it controversial because it creates a new class definition).

Because of this controversy, as of Java 9 there is a new idiom for conveniently constructing maps: the family of static Map.of methods.

With Java 9 or higher you can create the map you need as follows:

Map<String, Integer> map = Map.of(
    "cat", 2,
    "dog", 1,
    "llama", 0,
    "iguana", -1
);

With larger maps, this alternative syntax may be less error-prone:

Map<String, Integer> map = Map.ofEntries(
    Map.entry("cat", 2),
    Map.entry("dog", 1),
    Map.entry("llama", 0),
    Map.entry("iguana", -1)
);

(This is especially nice if Map.entry is statically imported instead of being referenced explicitly).

Besides only working with Java 9+, these new approaches are not quite equivalent to the previous one:

• They don't allow you to specify what Map implementation is used
• They only create immutable maps
• They don't create an anonymous subclass of Map

However, these differences shouldn't matter for many use cases, making this a good default approach for newer versions of Java.

Answer 5

Map<String,Integer> map = new HashMap<String, Integer>(){{
put("cat", 2);
put("dog", 1);
put("llama", 0);
put("iguana", -1);
}};