Bash get exit status of command when 'set -e' is active?

Question

I generally have -e set in my Bash scripts, but occasionally I would like to run a command and get the return value.

Without doing the set +e; som

Answer 1

From the bash manual:

The shell does not exit if the command that fails is [...] part of any command executed in a && or || list [...].

So, just do:

#!/bin/bash

set -eu

foo() {
  # exit code will be 0, 1, or 2
  return $(( RANDOM % 3 ))
}

ret=0
foo || ret=$?
echo "foo() exited with: $ret"

Example runs:

$ ./foo.sh
foo() exited with: 1
$ ./foo.sh
foo() exited with: 0
$ ./foo.sh
foo() exited with: 2

This is the canonical way of doing it.

Answer 2

Maybe try running the commands in question in a subshell, like this?

res=$(some-command > /dev/null; echo $?)

Answer 3

as an alternative

ans=0
some-command || ans=$?

Answer 4

Use a wrapper function to execute your commands:

function __e {
    set +e
    "$@"
    __r=$?
    set -e
}

__e yourcommand arg1 arg2

And use $__r instead of $?:

if [[ __r -eq 0 ]]; then
    echo "success"
else
    echo "failed"
fi

Another method to call commands in a pipe, only that you have to quote the pipe. This does a safe eval.

function __p {
    set +e
    local __A=() __I
    for (( __I = 1; __I <= $#; ++__I )); do
        if [[ "${!__I}" == '|' ]]; then
            __A+=('|')
        else
            __A+=("\"\$$__I\"")
        fi
    done
    eval "${__A[@]}"
    __r=$?
    set -e
}

Example:

__p echo abc '|' grep abc

And I actually prefer this syntax:

__p echo abc :: grep abc

Which I could do with

...
        if [[ ${!__I} == '::' ]]; then
...