Rounding time in Python

Question

What would be an elegant, efficient and Pythonic way to perform a h/m/s rounding operation on time related types in Python with control over the rounding resolution?

Answer 1

I use following code snippet to round to the next hour:

import datetime as dt

tNow  = dt.datetime.now()
# round to the next full hour
tNow -= dt.timedelta(minutes = tNow.minute, seconds = tNow.second, microseconds =  tNow.microsecond)
tNow += dt.timedelta(hours = 1)

Answer 2

I think I'd convert the time in seconds, and use standard modulo operation from that point.

20:11:13 = 20*3600 + 11*60 + 13 = 72673 seconds

72673 % 10 = 3

72673 % (10*60) = 73

This is the easiest solution I can think about.