Extract version number from file in shell script

Question

I\'m trying to write a bash script that increments the version number which is given in

{major}.{minor}.{revision}

For example.

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Answer 1

I prefer "cut" command for this kind of things

major=`echo $version | cut -d. -f1`
minor=`echo $version | cut -d. -f2`
revision=`echo $version | cut -d. -f3`
revision=`expr $revision + 1`

echo "$major.$minor.$revision"

I know this is not the shortest way, but for me it's simplest to understand and to read...

Answer 2

Yet another shell way (showing there's always more than one way to bugger around with this stuff...):

$ echo 1.2.3 | ( IFS=".$IFS" ; read a b c && echo $a.$b.$((c + 1)) )
1.2.4

So, we can do:

$ x=1.2.3
$ y=`echo $x | ( IFS=".$IFS" ; read a b c && echo $a.$b.$((c + 1)) )`
$ echo $y
1.2.4