I want to get the index of the current object when using fast enumeration, i.e.
for (MyClass *entry in savedArray) {
// What is the index of |entry| in |sav
A simple observation: If you initialize the index to -1 and then put the ++index as the first line in the for loop, doesn't that cover all bases (provided someone doesn't slip code in front of the increment)?
If you want to access the index or return outside block here is a piece of code that can be useful. (considering the array is an array of NSString).
- (NSInteger) findElemenent:(NSString *)key inArray:(NSArray *)array
{
__block NSInteger index = -1;
[array enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
if ([obj isEqualToString:key]) {
*stop = YES;
index = idx;
}
}];
return index;
}
I suppose the most blunt solution to this would be to simply increment an index manually.
NSUInteger indexInSavedArray = 0;
for (MyClass *entry in savedArray) {
indexInSavedArray++;
}
Alternatively, you could just not use fast enumeration.
for (NSUInteger indexInSavedArray = 0; indexInSavedArray < savedArray.count; indexInSavedArray++) {
[savedArray objectAtIndex:indexInSavedArray];
}
Look at the API for NSArray and you will see the method
- (void)enumerateObjectsUsingBlock:(void (^)(id obj, NSUInteger idx, BOOL *stop))block
So give that one a try
[savedArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
//... Do your usual stuff here
obj // This is the current object
idx // This is the index of the current object
stop // Set this to true if you want to stop
}];
This question has already been answered, but I thought I would add that counting iterations is actually the technique mentioned in the iOS Developer Library documentation:
NSArray *array = <#Get an array#>;
NSUInteger index = 0;
for (id element in array) {
NSLog(@"Element at index %u is: %@", index, element);
index++;
}
I was sure there would be a fancy trick, but I guess not. :)